[tex]\bf \qquad \textit{Amount for Exponential Decay}
\\\\
A=P(1 - r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &1750\\
r=rate\to 11\%\to \frac{11}{100}\to &0.11\\
t=\textit{elapsed time}\to &10\\
\end{cases}
\\\\\\
A=1750(1-0.11)^{10}\implies A=1750(0.89)^{10}\implies A\approx 545.68009877[/tex]
