Respuesta :
Hi there! The answer is C.
Explanation:
We have the following equation:
[tex] \frac{8}{15} = \frac{x}{6} [/tex]
To solve this type of equation (with an x in the denominator of a fraction) we must cross-multiply the numerator and the denominator.
[tex]15 \times x = 8 \times 6[/tex]
Multiply
[tex]15x = 40[/tex]
Divide both sides by 15.
[tex]x = \frac{40}{15} = 2 \frac{2}{3} [/tex]
~ Hope this helps you!
Explanation:
We have the following equation:
[tex] \frac{8}{15} = \frac{x}{6} [/tex]
To solve this type of equation (with an x in the denominator of a fraction) we must cross-multiply the numerator and the denominator.
[tex]15 \times x = 8 \times 6[/tex]
Multiply
[tex]15x = 40[/tex]
Divide both sides by 15.
[tex]x = \frac{40}{15} = 2 \frac{2}{3} [/tex]
~ Hope this helps you!
I believe the answer is C. "15x=48."
If you cross multiply the proportion that is the equation that results from it.
[tex] \frac{8}{15} [/tex] = [tex] \frac{x}{6} [/tex]
15×x=15x
8×6=48
15x=48
If you cross multiply the proportion that is the equation that results from it.
[tex] \frac{8}{15} [/tex] = [tex] \frac{x}{6} [/tex]
15×x=15x
8×6=48
15x=48