Respuesta :
Hi!!
Subtracting a negative is the same as adding a positive.
So we can write this as
[tex]- \frac{9}{12} + \frac{1}{3} [/tex]
We need to change [tex] \frac{1}{3} [/tex] to have the same denominator as [tex]- \frac{9}{12} [/tex].
[tex] \frac{1}{3} * \frac{4}{4} = \frac{4}{12} [/tex]
Now the equation is
[tex]- \frac{9}{12} + \frac{4}{12} [/tex]
Solve by adding the numerators.
[tex]- \frac{9}{12} + \frac{4}{12} = -\frac{5}{12}[/tex]
The answer is [tex] -\frac{5}{12}[/tex]
Hope this helps! :)
-Peredhel
Subtracting a negative is the same as adding a positive.
So we can write this as
[tex]- \frac{9}{12} + \frac{1}{3} [/tex]
We need to change [tex] \frac{1}{3} [/tex] to have the same denominator as [tex]- \frac{9}{12} [/tex].
[tex] \frac{1}{3} * \frac{4}{4} = \frac{4}{12} [/tex]
Now the equation is
[tex]- \frac{9}{12} + \frac{4}{12} [/tex]
Solve by adding the numerators.
[tex]- \frac{9}{12} + \frac{4}{12} = -\frac{5}{12}[/tex]
The answer is [tex] -\frac{5}{12}[/tex]
Hope this helps! :)
-Peredhel
Hi there!
[tex]\dfrac {- 9}{12}[/tex] - ( [tex]\dfrac {- 1}{3}[/tex] )
⇒ [tex]\dfrac {- 9}{12}[/tex] + [tex]\dfrac {1}{3}[/tex]
⇒ [tex]\dfrac {- 9 + 4}{12}[/tex] = [tex]\dfrac {- 5}{12}[/tex]
Hence,
Option 4ᵗʰ : [tex]\dfrac {- 5}{12}[/tex] is Correct.
~ Hope it helps!
[tex]\dfrac {- 9}{12}[/tex] - ( [tex]\dfrac {- 1}{3}[/tex] )
⇒ [tex]\dfrac {- 9}{12}[/tex] + [tex]\dfrac {1}{3}[/tex]
⇒ [tex]\dfrac {- 9 + 4}{12}[/tex] = [tex]\dfrac {- 5}{12}[/tex]
Hence,
Option 4ᵗʰ : [tex]\dfrac {- 5}{12}[/tex] is Correct.
~ Hope it helps!