Start by dividing both sides by 2 to get [tex]log(x)= \frac{1}{2}log(64) [/tex]. Doing the math on the right, keeping in mind that logs have an unwritten base of 10, gives us [tex] log_{10} (x)=.903089987[/tex]. Rewriting this in exponential form is [tex] 10^{.903089987}=x [/tex]. That means that x = 8. Not negative, only positive.
