we are given
[tex] \sum _{n=0}^4\:\left(1+3n\right) [/tex]
we can find it's sum
[tex] \sum _{n=0}^4\:\left(1+3n\right)=(1+3*0)+(1+3*1)+(1+3*2)+(1+3*3)+(1+3*4) [/tex]
[tex] \sum _{n=0}^4\:\left(1+3n\right)=35 [/tex]
now, we can find second sum
[tex] \sum _{i=2}^6\:\left(3i-5\right)=(3*2-5)+(3*3-5)+(3*4-5)+(3*5-5) + (3*6-5) [/tex]
[tex] \sum _{i=2}^6\:\left(3i-5\right)=35 [/tex]
so, we can see that
both sums are 35
so, their difference will be 0
option-A.........Answer
