The surface area of the pyramid will be 64.8 yd². So the correct option is C.
How to find the base's area of a right rectangular pyramid?
Suppose the base of the pyramid has length = l units, and width = w units.
Suppose that the height of the pyramid is of h units:
A right rectangular pyramid is a pyramid, with four slant sides, and a rectagular base, such that all the sides are congruent and the vertex is atop of the midpoint of the base rectangle.
The base is a rectangle with length = L units, and width = W units, so its area is:
[tex]b = l \times w\: \rm unit^2[/tex]
The surface area of the pyramid = a + 1/2(p)(h)
The surface area of the pyramid = 18+1/2( 18)(5.2)
The surface area of the pyramid = 18+46.8
The surface area of the pyramid =64.8
Therefore, The surface area of the pyramid will be 64.8 yd².
So the correct option is C.
Learn more about rectangular pyramid here:
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