we are given that ,
The combined area of two squares is 17 square meters.
Area of square=[tex] (side)^2 [/tex]
Let the side length of smaller square be x
The size of the larger Square are four times as long as the size of the smaller square
[tex] Area \ of \ smaller \ square \ =x^2 [/tex]
So Area of larger square=[tex] 4x^2 [/tex]
The combined Area is 17 square meter.
[tex] x^2+4x^2=17\\\\5x^2=17\\\\x=\sqrt{\frac{17}{5}} [/tex]
Hence the smaller square has the side length=[tex] \sqrt{\frac{17}{5}} [/tex]
So the larger square has side length=[tex] 2\sqrt{\frac{17}{5}} [/tex]
