The energy of this photon = 3.69 x 10⁻¹⁹ J
Explanation:
The energy of a photon is given by
[tex] E= \frac{h c}{\lambda} [/tex]
h= Planck's constant= 6.626 x 10⁻³⁴ J s
c= velocity of light= 3 x 10⁸ m/s
λ= wavelength= 538 nm= 538 x 10⁻⁹ m
so [tex] E= \frac{6.626\times 10^{-34}\times 3\times10^{8}}{538\times10^{-9}} [/tex]
E=3.69 x 10⁻¹⁹ J
