in parallelogram we know that diagonal are equal in length and intersecting at point
we know that value a diagonal is half the value of itself at intersecting point .
here H is the intersecting point of diagonals.
we know that DF=DH+HF
we know DH=HF
x+3=3y
so x-3y=-3......(1)
GE=GH+HE
GH=HE
2x-5=5y+2
2x-5y=7.....(2)
if we solve equation 1 and 2 by elimination method.
x=36 and y=13.
The diagonals of parallelogram bisect each other
So, DH=HF
x+3=3y
Subtracting 3 from both sides gives
x=3y-3
Also, GH=HE
2x-5=5y+2.
Plugging x=3y-3 in 2x-5=5y+2
We get, 2(3y-3)-5=5y+2
6y-6-5=5y+2
6y-11=5y+2
To solve for y, Let us subtract 5y from both sides
6y-5y-11=5y-5y+2
1y-11=0+2
Adding 11 on both sides, we get
y-11+11=2+11https://brainly.com/question/add?entry=1611
y=13
x is 3y-3
So, x=3(13)-3
x=39-3
Or, x=36
So, x=36 and y=13
