contestada

If the 140 g ball is moving horizontally at 25 m/s , and the catch is made when the ballplayer is at the highest point of his leap, what is his speed immediately after stopping the ball

Respuesta :

(.140*25)+(75*0)= 3.5

3.5 = (.140 + 75)v

(3.5)/(.140 + 75) = v = .04657

which rounds up to .05 m/s

Answer:

4.6 x 10(-2 power) m/s

Explanation:

Mastering Physics wants the answer like this.

Otras preguntas