graysamathecat
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I WILL VOTE MOST BRAINLY ANSWER. HELP ME PLEASE
Part A: Factor x2a2 + 3xa2 + 2a2. Show your work. (4 points)

Part B: Factor x2 + 2x + 1. Show your work. (3 points)

Part C: Factor x2 − 1. Show your work. (3 points)

Respuesta :

faryna
part A = x²a² + 3xa² + 2a²
= a²(x² + 3x + 2)
= a²(x+1)(x+2)

part B = x² + 2x + 1
= (x + 1)²

part C = x²-1
=x²-1²
=(x-1)(x+1)
altavistard

Part A: Factor x2a2 + 3xa2 + 2a2. Show your work. (4 points)

Important: Use "^" to denote exponentiation: x^2a^2 + 3xa^2 + 2a^2. Here a^2 is common to all three terms, and so we have a^2(x^2 + 3x + 2). Further, a^2(x^2 + 3x + 2) factors further: a^2(x+1)(x+2).

Part B: Factor x^2 + 2x + 1. The factors are (x+1)(x+1). Check this through multiplication.

Part C: Factor x^2 − 1 = x^2 - 1^2 is the difference of two squares. The factors are (x-1)(x+1). You've got to memorize this identity.

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