Let b/day = beats per day
Let d/yr = days per year
Let b/yr = beats per year
[tex](1.15e5b/day)(365d/yr)=41,975,000b/yr[/tex]
Answer: [tex]4.2\cdot10^{7}[/tex] times
Step-by-step explanation:
Given: The average human heart beats in one day=[tex]1.15\cdot10^5[/tex] times
The number of days in one year =[tex]3.65\cdot10^2[/tex]
Now, the number of times does the heart beat in one year is given by :-
[tex]1.15\cdot10^5\cdot3.65\cdot10^2\\\\=1.15\times3.65\times10^{5+2}......[\text{Since }a^m\cdot a^n=a^{m+n}]\\\\=4.1975\cdot10^{7}\approx4.2\times10^7[/tex]
Hence, the heart beat [tex]4.2\cdot10^{7}[/tex] times in one year.
