Respuesta :
Let a = aircraft 1 seats
Let b = aircraft 2 seats
Let c = aircraft 3 seats
From the information given above, let's make basic equations.
[tex]a=51+b[/tex]
[tex] b=b [/tex]
[tex]c=b-54[/tex]
[tex]a+b+c=411[/tex]
We can begin to plug in values we know.
[tex] 51+b+b+b-54=411 [/tex]
[tex]3b-3=411[/tex]
[tex]3b=414[/tex]
[tex]b=138[/tex]
We now know that the second aircraft has 138 seats. Now we can plug in this value to find the value of the other seats. Let's start with the first aircraft.
[tex]a=51+b[/tex]
[tex]a=51+138[/tex]
[tex]a=189[/tex]
We now know that the first aircraft has 189 seats. Let's now finally solve for the third aircraft.
[tex]c=b-54[/tex]
[tex]c=138-54[/tex]
[tex]c=84[/tex]
Finally, we know that aircraft 3 has 84 seats. To check our work, let's make sure that each of these values add up to 411.
[tex]a+b+c=411[/tex]
[tex]189+138+84=411[/tex]
[tex] 411=411 [/tex]
This is true, therefore the values are correct.
Aircraft 1: 189 seats
Aircraft 2: 138 seats
Aircraft 3: 84 seats
