First note that:
- [tex]2\dfrac{7}{16}=2+\dfrac{7}{16},[/tex]
- [tex]1\dfrac{7}{8}=1+\dfrac{7}{8}.[/tex]
Then add all three numbers:
[tex]2\dfrac{7}{16}+1\dfrac{7}{8}+\dfrac{1}{2}=2+\dfrac{7}{16}+1+\dfrac{7}{8}+\dfrac{1}{2}=(1+2)+\left(\dfrac{7}{16}+\dfrac{7}{8}+\dfrac{1}{2}\right)=3+\dfrac{7}{16}+\dfrac{14}{16}+\dfrac{8}{16}=3+\dfrac{7+14+8}{16}=3+\dfrac{29}{16}=3+1+\dfrac{13}{16}=4+\dfrac{13}{16}=4\dfrac{13}{16}.[/tex]
The total weight of books is [tex]4\dfrac{13}{16}[/tex] pounds that is less than 6 pounds.
Answer: Gina can ship all 3 books
