The pasture is in the shape of a rectangle only the widths are marked.
a. Let x be the width of the pasture as labeled. Write an expression for the length in terms of x.
b. Write an expression for the area of the pasture in terms of x.
(a) the hedge along the length . we need to consider the three sides for fencing.
To find the length we use the given information
Dennis plans to use 1150 ft of fence to enclose a rectangular pasture.
Perimeter of rectangle = 2L + 2W
the hedge along the length, so we perimeter becomes L + 2W
Perimeter = L +2W, Width is x and perimeter is 1150
1150 = L + 2x ( subtract 2x on both sides)
So length L = 1150 - 2x
(b)Area of rectangle = length * width
We got L = 1150 -2x and we know width is x
Area = (1150-2x)*x
[tex]Area = 1150x - 2x^2[/tex] square feet