Answer:
C₂₂H₂₄O₉N₂
Solution:
Step 1: Calculate %age of Elements;
%C = 1.1478 / 2 × 100 = 57.39%
%H = 0.104035 / 2 × 100 = 5.20%
%O = 0.62609 / 2.00 × 100 = 31.30%
%N = 100% -(57.39 + 5.20 + 31.30) = 6.11%
Step 2: Calculate Mass of Elements as;
C = (57.39 / 100 ) × 460 = 263.99 g
H = (5.20 / 100 ) × 460 = 23.92 g
O = (31.30 / 100 ) × 460 = 143.98 g
N = (6.11 / 100 ) × 460 = 28.10 g
Step 3: Calculate Moles of Elements:
C = 263.99 / 12 = 21.99 mol
H = 23.92 / 1 = 23.92 mol
O = 143.98 / 16 = 8.99 mol
N = 28.10 / 14 = 2.00 mol
Step 4: Calculate the simplest mole ratio as;
C H O N
21.99/2 : 23.92/2 : 8.99/2 : 2/2
10.99 11.96 4.49 1
≈ 11 ≈ 12 ≈ 4.5 1
Multiply by 2 to get the whole number for oxygen
22 24 9 2
Empirical Formula = C₂₂H₂₄O₉N₂
It is also the molecular formula because the mass of empirical formula is equal to molecular mass as,
= (12)₂₂ + (1)₂₄ + (16)₉ + (14)₂
= 264 + 24 + 144 + 28
= 460
