Respuesta :
[tex] \bf \qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{elapsed time}\\ \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y=0.35(2.3)^x\implies y=0.35(1+\stackrel{\stackrel{r}{\downarrow }}{1.3})^x \implies \stackrel{\textit{converting 1.3 to percent}}{1.3\cdot 100\implies 130\%} [/tex]
Answer:
B.
Step-by-step explanation:
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