Answer:
0
Step-by-step explanation:
We are given a function [tex]f(x) = 3(x+2)-4[/tex].
To find its inverse, we will put this function equal to y (or any other variable) and make x the subject.
[tex]y = 3(x+2)-4[/tex]
[tex]y+4 = 3x+6[/tex]
[tex]y+4-6 = 3x[/tex]
[tex]\frac{y-2}{3} = x[/tex]
So, [tex]f'(x) = \frac{x-2}{3}[/tex]
Now put x = 2 in this to get the value of inverse of this function:
[tex]f'(2)= \frac{(2)-2}{3}[/tex] [tex]= 0[/tex]
Therefore, the value of the inverse of this function when x = 2 is 0.
