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A pet store has three fish tanks, each holding a different volume of water and a different number of fish. Tank A holds 40 L and 5 fish. Tank B holds 100 L and 12 fish. Tank C holds 180L and 23 fish. Order the tanks by volume per fish from least to greatest.

Respuesta :

salatulmaghrib
For each tank just divide the number of L by the number of fish to get the volume or fish.
For tank A it is 40/5=8, for tank B it is 100/12=8.3, and for tank C it is 180/23=7.8.
If you number them least to greatest, it is (tank C, tank A, tank B$.

Answer:

The ordering of tanks in order of volume per fish from least to greatest is:

               Tank C → Tank A → Tank B

Step-by-step explanation:

Tank A :

It holds 40 L and 5 fish.

This means that the volume per fish is:

[tex]=\dfrac{\text{Volume\ of\ water\ in\ Tank}}{\text{Number\ of\ fish\ in\ tank}}[/tex]

i.e.

Volume per fish is: 40/5= 8 L per fish.

Tank B:

It holds 100 L and 12 fish.

This means that the volume per fish is:

           100/12=8.33 L per fish.

Tank C:

It holds 180L and 23 fish.

This means that the volume per fish is:

           180/23=7.83 L per fish.

  • This means that Tank C has least volume per fish i.e. 7.83 L per fish.
  • Then Tank A i.e. 8 L per fish and the greatest volume per fish is for Tank B i.e. 8.33 L per fish.

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