Respuesta :

4. g(-2) = 3(-2), g(0) = 3(0), and g(5) = 3(5)

g(-3) = -6

g(0) = 0

g(5) = 15

5. h(-2) = -2(-2)+9, h(0) = -2(0) + 9, and h(5) = -2(5) + 9

h(-2) = 4 + 9 = 13

h(0) = 0 + 9 = 9

h(5) = -10 + 9 = -1


Essentially, all you're doing is plugging the x value into every single "x" you see in that function.