10. [tex]3y \leq 2y+3\\3y - 2y \leq 3 \\ \\ y\leq 3\\Answer is B\\[/tex]
How to:
1. Solve the equation
2. If it is [tex]\leq[/tex] or [tex]\geq[/tex] mark a filled circle on the number.
3. If it simply less than or greater than then mark a hollow circle on the number.
4. If is less than then the line proceeds on the left and if it greater than then the line proceeds on the right side.
q7. [tex]4y+3\leq y+6 \\ 4y-y \leq 6-3 \\ 3y\leq 3\\ y\leq 1[/tex]
answer is C
q8. [tex]-2y> 2// -y >1 // y<-1[/tex]
Answer A
q9. [tex]\frac{y}{3} <-1 \\ y< -3[/tex]
Answer is D
