Answer-
[tex]f(2)= 6x^4-10x^3+40x-50=46[/tex]
Solution-
The given function is,
[tex]\Rightarrow f(x)= 6x^4-10x^3+40x-50[/tex]
Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,
[tex]\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50[/tex]
[tex]\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50[/tex]
[tex]\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50[/tex]
[tex]\Rightarrow f(2)= 96-80+80-50[/tex]
[tex]\Rightarrow f(2)= 96-50[/tex]
[tex]\Rightarrow f(2)= 46[/tex]
Therefore, f(2) was found to be 46.
