Respuesta :

imlittlestar

Let 'a' and 'b' the only outcomes of an event.  

The probability of occurring outcomes 'a' is written as p(a) and  

The probability of occurring outcomes 'b' is written as p(b)

The sum of probability of these event can be written as,                           p(a) +p(b)= 1

Here p(a)=0.73 and we need to find p(b)

We know that p(a) +p(b)= 1

     0.73 + p(b)= 1

p(b) = 1 - 0.73 = 0.27

therefore the probability of b, p(b)=0.27

Probability  of an event is the number of favorable outcomes divided by the total number of possible outcomes .The sum of probability always equals 1.

It is given A and B are the only outcomes. So the sum of  probability of A and B will be 1.

Given P (A)=0.73

We need to find P(B)

P(A)+P(B)=1.

P(B)=1-P(A)

P(B)=1-0.73.

P(B)=0.27.

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