Answer:
Given:-
The length of copper wire (L) = 270 cm
Area of cross-sectional (A) = 0.030 [tex]cm^2[/tex]
and specific resistance (ρ) = [tex]1.8 \times 10^{-6}[/tex] ohm-cm.
Use the formula R=(Specific resistance*L)/A, to calculate the Resistance(R)
then, [tex]R=\frac{1.8 \times 10^{-6} \times 270}{0.030}[/tex] ohm
Simplify:
R = 0.0162 ohm = [tex]1.62\times 10^{-2}[/tex] ohm
Therefore, the resistance of copper wire is, [tex]1.62\times 10^{-2}[/tex] Ω
