adult tickets to a play cost $22. tickets for children cost $15. tickets for a group of 11 people cost a total of $228. write and solve a system of equations to find how many children and how many adults were in the group

Respuesta :

Adults = 9

Children = 2


Let x be the number of adults.

11-x is the number of children.


22x + 15(11-x) = 228

22x + 165 - 15x = 228

22x - 15x = 228 - 165

7x = 63

7x / 7 = 63 / 7

x = 9  number of adults.


11 - x = 11 - 9 = 2 number of children.


To check:


22x + 15(11-x) = 228

22(9) + 15(11-9) = 228

198 + 30 = 228

228 = 228


(not my answer btw)

Answer:

2 children 9 adults.

Step-by-step explanation::

$22 for adults and $15 for children.

Let x and y represent the unknown values and A represents cost for adults and C represents cost for children

C(x) + A(y)=228 would be one equation for this to figure out the amount of children to adults.

Since there are 11 people we know the x and y values when added cannot equal more than 11.

15(1) + 22(10)=235 So that's not correct

15(2) + 22(9) = 228 so that's the correct answer.

You could also graph if you weren't figuring out children to adults:

y=mx+b. y-intercept would be 11 because that's the amount of people altogether. y=__x+11. y=-1x+11. because of rise over run (1/-1= -1). So, it would also be a linear decreasing function!

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