Respuesta :
Answer:
The number of chairs they buy is, 55
Step-by-step explanation:
Let x be the number of stools buy and y be the number of chairs buy.
As per the given condition : East high school need to buy 25 more chairs than stools.
i.e,
y = x +25 ......[1]
It is given that the chairs cost $32 each and the stools cost $ 28 each and the total budget is $ 2,620 then;
28x+32y = 2620 ......[2]
Substitute equation [1] into [2] we have:
[tex]28x + 32(x+25) = 2620[/tex]
using distributive property: [tex]a \cdot(b+c) = a\cdot b+ a\cdot c[/tex]
[tex]28x + 32x +800 = 2620[/tex]
Combine like terms:
[tex]60x + 800 = 2620[/tex]
Subtract 800 from both sides we have:
[tex]60x + 800 -800 = 2620 -800[/tex]
Simplify:
[tex]60x = 1820[/tex]
Divide both sides by 60 we have:
[tex]\frac{60x}{60} =\frac{1820}{60}[/tex]
Simplify:
x = 30.3333...
Since , the stools they buy are are in number so we have , x = 30 stools.
Substitute in equation [1] we have;
y = 30 + 25 = 55
Therefore, the number of chairs they buy is, 55 chairs.
