Respuesta :
Answer:
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Step-by-step explanation:
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For the polynomial, [tex]f(x)=x^4+21x^2-100[/tex], the roots are [tex]2,-2,j5,-j5[/tex].
For the polynomial, [tex]f(x)=x^3-5x^2-25x+125[/tex], the roots are [tex]5;5;-5[/tex].
For the polynomial, [tex]f(x)=x^4+21x^2-100[/tex], the degree is [tex]4[/tex] so, the polynomial is a quartic polynomial. The total number of roots are also [tex]4[/tex]. To find the roots of the polynomial, factorise it as
[tex]x^4+21x^2-100=0\\(x^2-4)(x^2+25)=0\\(x-2)(x+2)(x-j5)(x+j5)=0\\x=2;-2;j5;-j5[/tex]
For the polynomial, [tex]f(x)=x^3-5x^2-25x+125[/tex], the degree is [tex]3[/tex] so, the polynomial is a cubic polynomial. The total number of roots are also [tex]3[/tex]. To find the roots of the polynomial, factorise it as
[tex]x^3-5x^2-25x+125=0\\(x-5)(x^2-25)=0\\(x-5)(x-5)(x+5)=0\\x=5;5;-5[/tex]
Learn more about polynomials here:
https://brainly.com/question/15301188?referrer=searchResults