Answer: D. 176 grams
Explanation:
[tex]2O_2+CH_4\rightarrow CO_2+2H_2O[/tex]
As methane is a limiting reagent as it limits the formation of product and oxygen is the excess reagent as it is in excess.
According to the given balanced equation,
1 mole of methane produces 1 mole of [tex]CO_2[/tex]
Thus 4 moles of methane will produce 4 moles of [tex]CO_2[/tex]
Mass of [tex]CO_2={\text {no of moles}}\times {\text {Molar mass}}[/tex]
Mass of [tex]CO_2=4\times 44g/mol= 176g[/tex]
Thus 176 g of [tex]CO_2[/tex] is produced in the reaction of 4 moles of [tex]CH_4[/tex] in excess [tex]O_2[/tex].
