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A bucket of water with total mass 23 kg is attached to a rope, which in turn is wound around a 0.050-m radius cylinder at the top of a well. the bucket is raised to the top of the well and released. the bucket is moving with a speed of 8.0 m/s upon hitting the water surface in the well. what is the angular speed of the cylinder at this instant?

Respuesta :

As we know the relation between linear speed and angular speed as

[tex]v = R\omega[/tex]

we will say

[tex]v = 8 m/s[/tex]

[tex]R = 0.05 m[/tex]

so here we can say that angular speed will be given as

[tex]\omega = \frac{8}{0.05}[/tex]

[tex]\omega = 160 rad/s[/tex]

so it is rotating at angular speed 160 rad/s

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