The function below is written in vertex form or intercept form. Rewrite them in standard form and show your work.

y = -3(x-2)(x-4)

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aachen aachen · Answer 1 · 2019-02-01T06:36:50+01:00

Answer:

The standard form is: y = -3x² +18x -24.

Step-by-step explanation:

Given is y = -3(x-2)(x-4)

Using FOIL method to expand the parentheses:-

y = -3(x-2)(x-4)

y = -3(x² -2x -4x +8)

Combining like terms:-

y = -3(x² -6x +8)

Distributing -3 to the terms inside parentheses:-

y = -3x² +18x -24.

Hence, standard form is: y = -3x² +18x -24.

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athleticregina athleticregina · Answer 2 · 2019-02-01T06:37:00+01:00

Answer:

The standard form as [tex]y =-3x^2+18x-24[/tex]

Step-by-step explanation:

Given: A function which is written in vertex form or intercept form.

We have to re-write it in standard form that in terms of [tex]y=ax^2+bx+c[/tex]

Given [tex]y =-3 (x-2)(x-4)[/tex]

Multiply each term on the right side, we get,

[tex]y =-3[x(x-4)-2(x-4)][/tex]

[tex]y =-3[x^2-4x-2x+8][/tex]

[tex]y =-3[x^2-6x+8][/tex]

Multiply constant term , we get,

[tex]y =-3x^2+18x-24[/tex]

Thus , we have obtained the standard form as [tex]y =-3x^2+18x-24[/tex]