Answer: The correct answer is option (C).
Explanation:
Pressure of the gas = 101.3 kilopascal
Volume of the gas = 495 mL = 0.495 L
Temperature of the gas = 25°C = 298 K(0°C = 273 K)
Value of gas constant in in kilopascals =8.314 kPa L\K mol
According to the ideal gas equation:'
[tex]PV=nRT[/tex]
[tex]n=\frac{PV}{RT}=\frac{101.3 kPa\times 0.495 L}{8.314 kPa L/K mol\times 298 K}=0.0202 mol[/tex]Moles of carbon-dioxide gas = 0.0202 moles
[tex]CO_2+H_2O\rightarrow H_2CO_3[/tex].
According to reaction 1 mole of [tex]CO_2[/tex] gas gives 1 moles [tex]H_2CO_3[/tex], then 0.0202 moles of [tex]CO_2[/tex] will produce :[tex]\frac{1}{1}\times 0.0202 [/tex] moles of [tex]H_2CO_3[/tex] that 0.0202 moles.
Mass of [tex]H_2CO_3[/tex] = Moles Molar mass of [tex]H_2CO_3[/tex]
= [tex]0.0202 moles\times 62 g/mol=1.2524 g[/tex]
From the options given the closest value to our answer is of option(C).
Hence ,the correct answer is option C.
