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Urgent question in Mathematics. Solve this to get 15 points
[tex] {2}^{100} - {2}^{99} - {2}^{98} .... {2}^{2} - {2}^{1} - {2}^{0}[/tex]
a) 0
b) 1
c) 2
d) 2^50

Respuesta :

Answer:

1.

Step-by-step explanation:

Note that 2^4 - 2^3 = 16 - 8 = 8 = 2^3

In a similar way 2^6 - 2^5 = 64 - 32 = 32 = 2^5.

So 2^99 - 2^98 = 2^98 ,  2^98 - 2^97 = 2^97 ,  2^97 - 2^96 = 2^96 and so on.

Therefore when we come to the last 2 terms we have 2^1 - 2^0 = 2 - 1

= 1 , so the answer is 1.
the correct answer is B

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