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A roller coaster car is traveling down a track at 22 m/s. The car has a mass of 2000 kg. What is the Kinetic energy of the car?

A) 22,000 J
B) 968,000 J
C) 484,000 J
D) 44,000 J

Respuesta :

gabrieldavidmilGabe

I found out the correct answer! All you have to do is plug in the numbers 2000 into m and 22 into v. In the equation: x = 1/2 * m * v^2 Where x equals kinetic energy. So the answer is C)

nandhini123

The kinetic energy of the car is 484000 J

Explanation:

Given

Velocity = 22 m/s

Mass = 2000 kg

To Find:

Kinetic energy of the car= ?

Solution:

Kinetic energy of the car  is given by [tex]KE =\frac{1}{2} \times(mv^2)[/tex]

Where

m= mass of the car

v= velocity  

KE = kinetic energy

So, substituting the values

[tex]KE =\frac{1}{2} \times(mv^2)[/tex]

tex]KE = \frac{1}{2}\times(2000*22^2)[/tex]

[tex]KE = \frac{1}{2}\times(2000*484)[/tex]

[tex]KE = \frac{1}{2}\times(968000)[/tex]

[tex]KE = \frac{968000}{2}[/tex]

KE = 484000 J

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