Answer: 60 miles
Step-by-step explanation:
Let x denote the distance between his home and the place of appointment and t be the time taken by him at 40 mph.
Also, [tex]Distance= Speed\times time[/tex]
[tex]\\\Rightarrow\ x=40t.........................(1)[/tex]
Since he left the house 15 minutes late, he drove the car at 50 mph and arrive 3 minutes early for the appointment.
15 minutes=[tex]\frac{15}{60}\ hour=0.25\ hour[/tex]
3 minutes=[tex]\frac{3}{60}\ hour=0.05\ hour[/tex]
Then actual time taken by him =t-0.25-0.05=t-0.30
[tex]\\\Rightarrow\ x=50(t-0.30)\\\Rightarrow\ x=50t-15.........................(2)[/tex]
From (1) and (2), we have
[tex]40t=50t-15\\\Rightarrow\ 10t=15\\\Rightarrow\ t=\frac{3}{2}\ hour[/tex]
Put the value of t in (1), we get
[tex]x=40\times\frac{3}{2}=60\ miles.........................(1)[/tex]
Hence, the distance between his home and the place of appointment = 60 miles.
Answer:
Simple
Step-by-step explanation:
Do the 163836 carry the 2 to get 328749.
