What would the difference of spectral lines emitted by hydrogen gas in distant galaxies which is normally found at a wavelength of 21 cm on earth, be observed at 21.1 centimeters?

Respuesta :

As we know by Doppler's effect

[tex]\frac{\Delta \lambda}{\lambda} = \frac{v}{c}[/tex]

so here we know that

[tex]\lambda' = 21.1 cm[/tex]

[tex]\lambda = 21 cm[/tex]

from above formula we have

[tex]\frac{21.1 - 21}{21} = \frac{v}{3 \times 10^8}[/tex]

[tex]\frac{0.1}{21} = \frac{v}{3 \times 10^8}[/tex]

[tex]v = 3 \times 10^8 \times \frac{0.1}{21}[/tex]

[tex]v = 1.43 \times 10^6 m/s[/tex]

so the galaxy is moving away from earth with above speed due to which we got larger wavelength