Answer:
In the first row, A = 1, B = 2, C = 4, D = 8, E = 16, F= 32, G = 64, H = 128
Step-by-step explanation:
We are given the beginning of the sequence: 1, 2, 4, ...
We can see that each time, the number of pennies is doubled to find the next number. This means the next ones would be 4(2) = 8; 8(2) = 16; 16(2) = 32; 32(2) = 64; 64(2) = 128
The pennies placed on the squares D, E, F, G, and H will be 8, 16, 32, 64, and 128 pennies.
Given:
There are 8 rows and 8 columns, which means 64 squares on a chessboard.
We are placing 1 penny on Row 1 Column A, 2 pennies on Row 1 Column B, 4 pennies on Row 1 Column C, and so on.
So, we are increasing the number of pennies twice the amount of the previous square.
So, the pennies on next squares will be,
[tex]Column\;D=2\times 4=8\\Column\;E=2\times 8=16\\Column\;F=2\times 16=32\\Column\;G=2\times 32=64\\Column\;H=2\times 64=128[/tex]
Therefore, the pennies placed on the squares D, E, F, G, and H will be 8, 16, 32, 64, and 128 pennies.
For more details, refer to the link:
https://brainly.com/question/24378828
