Answer:
[tex]\frac{-1}{2}[/tex]
Step-by-step explanation:
We are given that a fundtion
[tex]y=\frac{-4x^6+6x+3}{8x^6+9x+3}[/tex]
We have to find the horizontal asymptote of the given function
We know that when degree of numerator and degree of denominator are equal then to get horizontal asymptote we divide the coefficient of heighest power of x in numerator by the coefficient of heighest power of x in denominator .
There are degree of both numerator and denominator are same .
Therefore, horizontal asymptote=[tex]\frac{-4}{8}[/tex]
Horizontal asymptote=[tex]\frac{-1}{2}[/tex]
Hence, the horizontal asymptote of given graph =[tex]\frac{-1}{2}[/tex]
