contestada

Consider this function.

f(x) = 6x2 − 11x − 10.

What are the zeros of the function? A) x = 5/2 and x = − 2/3 B) x = − 5/2 and x = 2/3 C) x = 2/5 and x = − 2/3 D) x = − 2/5 and x = 3/2

Respuesta :

luisejr77

Answer: A) [tex]x=\frac{5}{2}[/tex] and  [tex]x=-\frac{2}{3}[/tex]

Step-by-step explanation:

Make the quadratic function [tex]f(x)=6x^2-11x-10[/tex] equal to zero:

[tex]6x^2-11x-10=0[/tex]

Having the form [tex]ax^2+bx+c=0[/tex], the zeros can be calculated with a formula called "Quadratic formula":

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

Then:

Identify a, b and c:

[tex]a=6\\b=-11\\c=-10[/tex]

Finally, substitute them into  the Quadratic formula:

[tex]x=\frac{-(-11)\±\sqrt{(-11)^2-4(6)(-10)}}{2(6)}\\\\x=\frac{11\±\sqrt{361}}{12}\\\\x=-\frac{2}{3}\\\\x=\frac{5}{2}[/tex]

Answer:

2, 3, 5

Step-by-step explanation:

just took it

Otras preguntas