Answer:
The diameter of the base of the cylinder is [tex]6\ yd[/tex]
Step-by-step explanation:
we know that
The volume of a right circular cylinder is equal to
[tex]V=\pi r^{2}H[/tex]
In this problem we have
[tex]V=72\pi\ yd^{3}[/tex]
[tex]H=8\ yd[/tex]
substitute and solve for r
[tex]72\pi=\pi r^{2}(8)[/tex]
[tex]r^{2}=9[/tex]
[tex]r=3\ yd[/tex]
Find the diameter D
[tex]D=2r[/tex] ------>[tex]D=2(3)=6\ yd[/tex]
