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A chemist dissolves 660.mg of pure hydroiodic acid in enough water to make up 300.mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places.

Respuesta :

Tdono01
660mg = 0.660g
300mL = 0.300L

0.660g/0.300L = 2.2M

ICE Box

HI + H2O --> H3O + I-
I. 2.2M 0M 0M
C -x +x +x
E 2.2M x x

You would need k to find x using the equation k = [H3O][I-]/[HI]. To find the pH, use the equation pH = -log[H3O].

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