Answer:
Step-by-step explanation:
Remark
x is going to be the same thing as the hypotenuse of ΔRST. Find that and you have x.
Givens
<STR = 60°
RT = 2√3
Solution
Sin(60°) = opposite / hypotenuse
Sin(60°) = √3 / 2
Sin (60°)= 2 √3 / hypotenuse
hypotenuse = 2√3 // sin(60°)
hypoteneuse = 2√3 /√3/2
[tex]\text{hypotenuse = }\dfrac{2\sqrt{3}}{\dfrac{\sqrt{3} }{2}} = 2*2[/tex]
The √3's cancel. The answer is 4
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ΔRTQ is a right angle isosceles triangle
∴RT = RQ
X = 4
