Two balloons are charged with an identical quantity and type of charge:-4 nC. They are held apart at a separation distance of 70 cm. Determine the magnitude of the electrical force of repulsion between them.

Respuesta :

Answer:

[tex]2.9\cdot 10^{-7}N[/tex]

Explanation:

The electrostatic force between the two balloons is given by:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

[tex]k=9\cdot 10^9 Nm^2 C^{-2}[/tex] is the Coulomb's constant

[tex]q_1=q_2=-4 nC=-4\cdot 10^{-9}C[/tex] is the charge on each balloon

[tex]r=70 cm=0.7 m[/tex] is the distance between the balloons

Substituting into the formula, we find

[tex]F=(9\cdot 10^9 Nm^2C^{-2})\frac{(-4\cdot 10^{-9}C)^2}{(0.70 m)^2}=2.9\cdot 10^{-7}N[/tex]