Respuesta :
Answer:
[tex]\large\boxed{B)\ y=(x-3)^2+9}[/tex]
Step-by-step explanation:
[tex]\text{The vertex form of equation}\ y=ax^2+bx+c:\\\\y=a(x-h)^2+k\\\\h=\dfrac{-b}{2a},\ k=f(h)\\\\\text{We have the equation:}\ y=x^2-6x+18\\\\a=1,\ b=-6,\ c=18\\\\\text{Substitute:}\\\\h=\dfrac{-(-6)}{2(1)}=\dfrac{6}{2}=3\\\\k=f(3)=3^2-6(3)+18=9-18+18=9[/tex]
Answer:
the answer is B
Step-by-step explanation:
i just did it on usa testprep trust me