Respuesta :
Answer:
- 0.1255 M
Explanation:
1) Data:
Base: NaOH
Vb = 15.00 ml = 15.00 / 1,000 liter
Mb = ?
Acid: H₂SO₄
Va = 17.88 ml = 17.88 / 1,000 liter
Ma = 0.1053
2) Chemical reaction:
The titration is an acid-base (neutralization) reaction to yield a salt and water:
- Acid + Base → Salt + Water
- H₂SO₄ (aq) + NaOH(aq) → Na₂SO₄ (aq) + H₂O (l)
3) Balanced chemical equation:
- H₂SO₄ (aq) + 2 NaOH(aq) → Na₂SO₄ (aq) + 2H₂O (l)
Placing coefficient 2 in front of NaOH and H₂O balances the equation
4) Stoichiometric mole ratio:
The coefficients of the balanced chemical equation show that 1 mole of H₂SO₄ react with 2 moles of NaOH. Hence, the mole ratio is:
- 1 mole H₂SO₄ : 2 mole NaOH
5) Calculations:
a) Molarity formula: M = n / V (in liter)
⇒ n = M × V
b) Nunber of moles of acid:
- nₐ = Ma × Va = 0.1053 (17.88 / 1,000)
c) Number of moles of base, nb:
- nb = Mb × Vb = Mb × (15.00 / 1,000)
d) At equivalence point number of moles of acid = number of moles of base
- nₐ = nb
- 0.1053 × (17.88 / 1,000) = Mb × (15.00 / 1,000)
- Mb = 0.1053 × 17.88 / 15.00 = 0.1255 mole/liter = 0.1255 M
Answer: The concentration of NaOH solution is 0.25 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
According to the neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of [tex]H_2SO_4[/tex] solution = 0.1053 M
[tex]V_1[/tex] = volume of [tex]H_2SO_4[/tex] solution = 17.88 ml
[tex]M_2[/tex] = molarity of [tex]NaOH[/tex] solution = 0.46 M
[tex]V_2[/tex] = volume of [tex]NaOH[/tex] solution = 15.0 ml
[tex]n_1[/tex] = valency of [tex]H_2SO_4[/tex] = 2
[tex]n_2[/tex] = valency of [tex]NaOH[/tex] = 1
[tex]2\times 0.1053M\times 17.88=1\times M_2\times 15[/tex]
[tex]M_2=0.25[/tex]
Therefore, the concentration of NaOH solution is 0.25 M