Respuesta :
[tex]
3-2z=\frac{1}{10} \\
30-20z=1\\
-20z=-29 \\
z=\frac{-29}{-20} \Longrightarrow z=\boxed{1.45}
[/tex]
For this case we have the following equation:
[tex]3-2z = \frac {1} {10}[/tex]
We must find the value of z that represents the solution of the equation:
We follow the steps below:
We multiply by 10 on both sides of the equation:
[tex]10 (3-2z) = 1[/tex]
We apply distributive property to the terms of parentheses;
[tex]30-20z = 1[/tex]
We subtract 30 from both sides of the equation:
[tex]-20z = 1-30\\-20z = -29[/tex]
We divide between -20 on both sides of the equation:
[tex]z = \frac {-29} {- 20}\\z = \frac {29} {20}\\z = 1.45[/tex]
If we substitute the value of z in the original equation, equality is satisfied.
Answer:
[tex]z = 1.45[/tex]