Answer:
C 0.85 j/g*k
Explanation:
The specific heat capacity of a material is given by:
[tex]C_s = \frac{Q}{m \Delta T}[/tex]
where
Q is the amount of heat supplied to the object
m is the mass of the object
[tex]\Delta T[/tex] is the increase in temperature of the object
For the object in this problem, we have
m = 117 g is the mass
Q = 1200 J is the heat supplied
[tex]\Delta T=12^{\circ}[/tex] is the increase in temperature
Substituting into the formula, we find the specific heat:
[tex]C_s = \frac{1200 J}{(117 g)(12^{\circ})}=0.85 J/gC[/tex]
