Respuesta :
Answer:
From the information provided we have:
PD ≅ RD (= 11)
∠CPD ≅ ∠CRD (= 90°)
They both have CD as the hypotenuse.
=> ΔCPD ≅ ΔCRD
=> ∠PCD ≅ ∠RCD
Now we know that:
∠RCP = ∠PCD + ∠RCD
∠RCP = 2 · ∠RCD
∠RCP = 2 · 33° = 66°
So the answer is B
Answer: B. 66°
Step-by-step explanation:
In then figure figure , we consider two triangle ΔPCD and Δ RCD in which
∠P ≅ ∠R = 90°
PD≅RD =11
CD≅CD [Reflexive Property]
Hence, By HL theorem we have
ΔPCD ≅ Δ RCD
[ HL theorem says that if the hypotenuse and a leg of a right triangle are congruent to the hypotenuse and a leg of other right triangle, then the triangles are said to be congruent.]
Now , By CPCTC we have
∠PCD≅∠RCD
Then , ∠RCP = 33°+33°=66°