The value of the given expression is equal to the [tex]\frac{29b}{5}-3\frac{17}{30}[/tex].
We have given that,
[tex]5\frac{4}{5}b+6\frac{3}{4}-\left(2\frac{11}{15}+7\frac{7}{12}\right)[/tex]
We have to determine the,
[tex]=\frac{29}{5}b+6\frac{3}{4}-\left(2\frac{11}{15}+7\frac{7}{12}\right)[/tex]
The expression consists of numbers and arithmetic operators. It does not contain equality or inequality symbols. The expression consists of unknown variables.
[tex]=\frac{29}{5}b+\frac{27}{4}-\left(2\frac{11}{15}+7\frac{7}{12}\right)[/tex]
[tex]=\frac{29}{5}b+\frac{27}{4}-\left(\frac{41}{15}+7\frac{7}{12}\right)[/tex]
[tex]=\frac{29}{5}b+\frac{27}{4}-\left(\frac{41}{15}+\frac{91}{12}\right)[/tex]
[tex]=\frac{29b}{5}+\frac{27}{4}-\frac{619}{60}[/tex]
[tex]=\frac{29b}{5}-\frac{107}{30}[/tex]
[tex]=\frac{29b}{5}-3\frac{17}{30}[/tex]
The value of the given expression is equal to the [tex]\frac{29b}{5}-3\frac{17}{30}[/tex].
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