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A copper sphere was moving at 25 m/s when it hit another object. This caused all of the KE to be converted into thermal energy for the copper sphere. If the specific heat capacity of copper is 387 J/(kg ⋅ C°), what was the increase in temperature?

0.23 C°
0.81 C°
1.3 C°
2.1 C°

Respuesta :

Answer:

[tex]\Delta T = 0.81 ^oC[/tex]

Explanation:

As we know by energy conservation

All its kinetic energy will convert into thermal energy to raise its temperature

[tex]\frac{1}{2}mv^2 = ms\Delta T[/tex]

now divide both sides by mass of the object

[tex]\frac{1}{2}v^2 = s\Delta T[/tex]

so change in temperature is given as

[tex]\Delta T = \frac{v^2}{2s}[/tex]

[tex]\Delta T = \frac{25^2}{2\times 387}[/tex]

[tex]\Delta T = 0.81^oC[/tex]

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