Answer:
61 second I would say but what is the weight of the rock?
Answer:
Option B. 7.8 seconds
Step-by-step explanation:
Shyanne drops a rock from a hill at initial height of 975 feet above the ground level.
We have to calculate the time taken by rock to hit the ground.
As we know the formula of motion under gravity is
h = ut + [tex]\frac{1}{2}gt^{2}[/tex]
Here h = initial height = 975 feet
u = initial velocity = 0
t = time taken by the rock to hit the ground
g = 32.174 [tex]\frac{\text{Feet}}{\text{Second}^{2}}[/tex]
Now we plug in these values in the formula
975 = 0 + [tex]\frac{1}{2}(32.174)(t)^{2}[/tex]
975 = 16.087t²
t² = [tex]\frac{975}{16.087}[/tex]
t = [tex]\sqrt{60.60}[/tex]
t = 7.78 ≈ 7.8 seconds
Option B. 7.8 seconds is the answer.
